The Chiefs lost to the Broncos 24-17 on Sunday and had a chance to at least tie the game at the very end. Kansas City kept Peyton Manning off the field for an enormous chunk of the second half. The Broncos offense had only two drives after halftime (not including the final kneel down), one for a punt, one for a field goal, totaling just 8:51 in possession. The longest drive came from the Chiefs at the very start of the second half, where they ran 23 plays, taking 10 minutes off the clock... and ultimately missed a field goal. This got me thinking, how does drive length (in minutes) affect the probability of a team scoring?
First, here's a look at the ridiculous drive using our Markov model:
Last, the fact that John Fox did not use any timeouts on the Chiefs' last drive of the game is flummoxing. Kansas City had a 1st-and-Goal from the nine, down seven points with 1:45 left in the game. The only way that drive lasts longer than four plays is if there is an automatic first down penalty. If the Chiefs do not score, Denver wins anyway as the Chiefs only had one timeout remaining. If the Chiefs do score, you want Peyton Manning to have as much time as possible to allow the offense to get into field goal range. Denver held on to all three timeouts. If the Chiefs had scored on fourth down, Peyton would have had only had 18 seconds to do anything with the ball. Peyton with over a minute to get into field goal range leaves you with a high probability of winning the game. Peyton with 18 seconds most likely means overtime -- much closer to a coin flip.
Keith Goldner is the Chief Analyst at numberFire.com - The leading fantasy sports analytics platform - and creator of Drive-By Football. Follow him on twitter @drivebyfootball or check out numberFire on Facebook. Check out numberFire's new iOS App in the app store now.